Jawab:
3x⁴-7x²-5x-4/2x²+5x+8 = x⁴(3-7/x²-5/x³)/x²(2+5/x+8/x²)
= x²(3-7/x²-5/x³)/(2+5/x+8/x²)
= ∞²(3-7/∞²-5/∞³)/(2+5/∞+8/∞²)
= ∞²(3-0-0)/(2+0+0)
= 3.∞² = ∞
3. 3x³+7x²-4x+9/7x³-5x²-3x+5 = (x³(3+7/x-4/x²+9/x³))/x³(7-5/x-3/x²+5/x³)
= (3+7/x-4/x²+9/x³)/(7-5/x-3/x²+5/x³)
= (3+7/∞ - 4/∞² + 9/∞³)/(7-5/∞ - 3/∞² + 5/∞³)
= (3+0-0+0)/(7-0-0+0)
= 3/7
4. 2x⁴-7x²+5/2x⁴-5x²-3x+5 = x⁴(2-7/x²+5/x⁴)/x⁴(2-5/x²-3/x³+5/x⁴)
= (2-7/x²+5/x⁴)/(2-5/x²-3/x³+5/x⁴)
= 2/2 = 1
5. 2x²+7x-3/x³-5x²+6x = x²(2+7/x-3/x²)/x³(1-5/x+5/x²)
= (2+7/x-3/x²)/x(1-5/x+5/x²)
= 2/∞.1
= 2/∞ = 2.1/∞ = 0
Penjelasan dengan langkah-langkah:
˜”*°•.˜”*°• Answer by jimin •°*”˜.•°*”˜
♥ Answer by SUGA ♥
